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Cool vids bro.
ОтветитьI thought you need a reduced row echelon form(rref)
Ответитьthank you!!!
ОтветитьIn REF shouldn't the main diagonals be 1's? Never mind, you're doing (Reduced Echelon Form), I though you were doing (Row Echelon Form).
ОтветитьIs the dimension of the row space the same as the dimension of the column space of a matrix?
ОтветитьSuppose that you identify the non-zero rows of the row reduced
matrix, but then take the corresponding rows of the original matrix,
will this in general give a basis for the row space?
At last couldnt we divide 1st row to make pivot 1 and divide 2th row by 6 to make pivot 1? And basis will change what ?!
Ответитьnice
ОтветитьThere's four numbers in each vector in the basis which has 2 dimensions so how o you represent that in r 2 graph ..
ОтветитьThis is exactly what I needed, thank you!
ОтветитьThanks a lot!
ОтветитьGreat video, helped a lot. Thank you
Ответитьthanks a bunch
ОтветитьCan you find the basis row reducing A^T and finding the pivots on that matrix?
ОтветитьThank you
ОтветитьThank you so much. You are the best engineer
ОтветитьGrazie mille!
ОтветитьThank you so much. Was really sick and missed a whole bunch of stuff.
ОтветитьChange your channel name to "The God" or "The ultimate Savior" sir.
ОтветитьWhy tf did my textbook make this so hard 😂
Ответитьthank you
Ответитьthank you so much
ОтветитьExcellent
ОтветитьI fucking love you 😭. The struggle i had with these... Thank you!!!!!!!!!!!!!!
ОтветитьTHANK YOU
ОтветитьThe basis of row sapce of A contain 2 vactors that's why it's dimension is 2 but those 2 vectors are 4 dimensional Bec they have 4 components. So does it make sense a 4 dimensional vectors exist in 2 dimensional subspace. Please reply 🙏
ОтветитьTY sir
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