JEEM 2022 Atoms energy

14 An electron with speed v and a photon with speed c have the same de Broglie wavelength. If the kinetic energy and momentum of electron are Ee and pe and that of photon are Eph and pph respectively. Which of the following is correct?

Ee/Eph = 2c/v
Ee/Eph = v/2c
pe/pph = 2c/v
pe/pph = v/2c

de broglie wavelength, momentum

Тэги:

#RUTHERFORD’S_NUCLEAR_MODEL_OF_ATOM #ATOMIC_SPECTRA #Electron_orbits #BOHR_MODEL_OF_THE_HYDROGEN_ATOM #Energy_levels #THE_LINE_SPECTRA_OF_THE_HYDROGEN_ATOM #DE_BROGLIE’S_EXPLANATION_OF_BOHR’S_SECOND_POSTULATE_OF_QUANTISATION

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